Question

The area of a Trapezium of height 8 M is 208 m square sum of its parallel sides is​

Answer 1

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Area of trapezium= 248 m²

Height (h)= 8 m

Let the one parallel side be= x m

Other parallel side =( x-4) m

Area of trapezium = 1/2 ( sum of parallel sides) × height

• $248 = \frac{1}{2} ( X+ X- 4)× 8$

• $248 = (2x - 4) × 4$

• $\frac{248}{4} = 2x-4$

• $62 = 2x-4$

• $62+4= 2x$

• $66= 2x$

• $X= \frac{66}{2}$

• $X= 33$

$One \: \: parallel \: \: \: side \: \: \: (X) \: \: = \: \: 33 m$

$Other \: \: parallel \: \: side \: \: (x -4)= 33-4= 29 m$

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Hope it's Helpful :)