Question

the area of a trapezium shaped field is 480m² the distance between two parallel sides is 15m and one of the parallel side is 20m find the other parallel side​

Answer 1

Answer:

44m

Step-by-step explanation:

Area of trapezium= 2×(sum of parallel sides)×height

Let other parallel side be x

So we get,

480=((20+x)/2)×15

480/15=(20+x)/2

(480×2)/15=20+x

(960/15)-20=x

64-20=x

44=x

Other parallel side is 44m

Answer 2

$\large{\dag{\underline{\underline{\sf{\pmb{Question: - }}}}}}$

The area of a trapezium shaped field is 480m² the distance between two parallel sides is 15m and one of the parallel side is 20m find the other parallel side.

$\large{\dag{\underline{\underline{\sf{\pmb{Required \: Answer}}}}}}$

$\\ \dag{\underline{\underline{\sf{\pmb{Given: - }}}}}$

• Area of the trapezium shaped field is 480m²
• Height of the trapezium is 15m
• One of the parallel side is 20m

$\\ \dag{\underline{\underline{\sf{\pmb{To \: Find: - }}}}}$

• The other parallel side.

$\\ \dag{\underline{\underline{\sf{\pmb{Solution: - }}}}}$

We know that:-

$\\ \underline{\boxed{\tt{Area \: of \: a \: trapezium \: \: A = \bold{\dfrac{1}{2}(a + b)h} \: \: sq.units}}}$

Where,

• a and b are the parallel sides of the trapezium
• h is the height or the distance between two parallel sides.

According to the question:-

• Area A= 480m²
• Height h = 15m
• One of the parallel sides a = 20m

Let b be the other parallel side.

Substituting the values:-

$\\ \sf{\bold{480 = \dfrac{1}{2} \times (20 + b) \times 15}}$

$\\ \sf{\implies{ \dfrac{1}{2} \times (20 + b) \times 15 = 480}}$

$\\ \sf{\implies{\dfrac{1}{2} \times (20 + b) = \dfrac{480}{15}}}$

$\\ \sf{\implies{20 + b = 32 \times 2}}$

$\\ \sf{\implies{b = 64 - 20}}$

$\\ \sf{\therefore{\red{b = 44}}}$

Therefore, other parallel side is 44m