Question

The area of a trapezium shaped field is 480m², The height is 15m and one of the parallel side is 20m. Find the other side.

Answer 1

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Answer...

Solution :

We have,

Area of trapezium ABCD = 480m²

$= > \frac{1}{2} (AB +CD) \times AL = 480 \\ \\ = > \frac{1}{2} (20 + CD) \times 15 = 480 \\ \\ = > 20 + CD = \frac{480 \times 2}{15} \\ \\ = > 20 + CD = 32 \times 2 \\ \\ = > 20 + CD = 64 \\ \\ = > CD = 64 - 20 = 44$


Hence, the other side of the trapezium is 44m.


Hope it helped ☺☺☺☺

Answer 2

given
height=15 ,one parallel side=20
let other parallel side be x
we know, area of trapezium=1/2*height *sum of parallel sides
1/2*15*20+x =480
1/2 *300 +15x =480
1/2 +x=480/300×15
1/2 +x=