Question

The area of a trapezium whose bases are 12 cm and 20 cm, respectively, and altitude 10cm is

Answer 1

Step-by-step explanation:

$area \: of \: trapezium = \frac{1}{2} (a + b) \times altitude$

$= \frac{1}{2} (12 + 20) \times 10$

$= \frac{1}{2} \times 32 \times 10$

$= 1 \times 16 \times 10$

$= 160$

Answer 2

Answer:

160 cm²

Step-by-step explanation:

Given

The length of the parallel bases of the trapezium

a = 12 cm, b = 20 cm

The height of the trapezium h = 10 cm

∴The area of the trapezium = 1/2*(h)(a + b) sq.units

                                              = 1/2*(10)(12 + 20)  cm²

                                              = 5*32  cm²

∴The area of the trapezium = 160 cm²