Question

The area of a trapezium whose bases are 12 m and 90 dm and its altitude is 60 dm is

Answer 1

Step-by-step explanation:

Given: Base of trapezium (b

1

)=28 dm=

10

28

m=2.8 m[∵1 dm=

10

1

m]

Base of trapezium (b

2

)=3 dm=

10

3

m=0.3 m

Height of trapezium (h)=25 dm=

10

25

m=2.5 m

Now, Area of trapezium =

2

1

×(b

1

+b

2

)×h

=

2

1

×(2.8+0.3)×2.5

=

2

1

×3.1×2.5

=3.875 m

2