the area of a trapisium of height =3cm ir 36cm square one of the parallel sides is b1 9cm find the other b2 =?
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height of the trapezium =h= 3cm
area = A = 36cm²
length of one parallel side = b1 = 9cm
b2 =?
(b1+b2)h/2 = A
(9+b2)*3/2 = 36
9+b2 = (36*2)/3
9+b2 = 24
b2 = 24-9
b2 =15 cm
area = A = 36cm²
length of one parallel side = b1 = 9cm
b2 =?
(b1+b2)h/2 = A
(9+b2)*3/2 = 36
9+b2 = (36*2)/3
9+b2 = 24
b2 = 24-9
b2 =15 cm
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