the area of a trapizium is180 and its height is 9cm if one of the parallel sides islonger than the other by 6cm find the two parallel sides
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Let one of the parallel side be x cm
so , larger side ( parallel ) = ( x + 6 ) cm
Area ( given ) = 180 cm²
Height ( given ) = 9 cm
Now ,
we know that ,
area of trapezium =
1/2 ( sum of parallel sides ) * height .
A / q ,
1 / 2 * ( x + x + 6 ) * 9 = 180
=> ( 2x + 6 ) * 9= 180 * 2
=> 2x + 6 = 180 * 2 / 9
=> 2x + 6 = 20 * 2
=> 2x = 40 - 6
=> 2x = 34
=> x = 34 / 2
=> x = 17 .
So ,
smaller side = 17 cm
Larger side = ( 1 7+ 6 ) cm = 23 cm .
thanks :)
Let one of the parallel side be x cm
so , larger side ( parallel ) = ( x + 6 ) cm
Area ( given ) = 180 cm²
Height ( given ) = 9 cm
Now ,
we know that ,
area of trapezium =
1/2 ( sum of parallel sides ) * height .
A / q ,
1 / 2 * ( x + x + 6 ) * 9 = 180
=> ( 2x + 6 ) * 9= 180 * 2
=> 2x + 6 = 180 * 2 / 9
=> 2x + 6 = 20 * 2
=> 2x = 40 - 6
=> 2x = 34
=> x = 34 / 2
=> x = 17 .
So ,
smaller side = 17 cm
Larger side = ( 1 7+ 6 ) cm = 23 cm .
thanks :)
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