The area of a triangle ABC is 10.8 cm2.if CP=PB and 2AQ= QB the the area of triangel APQ IS
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Step-by-step explanation:
let say BC = b cm
and AB = a cm
x is the angle between bc & ba
then area of triangle ABC
= (1/2)baSinx = 10.8 cm^2
area of triangle BPQ
BP = (1/2)BC = b/2
AQ + QB = AB
QB/2 + QB = AB
3QB/2 = AB
QB = 2AB/3 = 2a/3
area of triangle bpq
= (1/2)(b/2)(2a/3) Sinx
= (1/3) (1/2)baSinx
= (1/3)*10.8
= 3.6 cm^2
area of triangle APC
= (1/2) area of triangle abc
as p is mid point
= (1/2)* 10.8 = 5.4 cm^2
area of triangle
BPQ + APQ + APC = ABC
3.6 + APQ + 5.4 = 10.8
Area of APQ = 1.8 cm^2
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