Math, asked by DrCockTail40, 1 day ago

the area of a triangle if a =51cm , b =70 and Angle C=41 degree is​

Answers

Answered by parweenshama263
0

Answer:

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Calculate the area of the triangle whose sides are 18 cm, 24 cm and 30 cm in length. Also find the length of the altitude corresponding to the smallest side.

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Correct option is A)

According to the Heron's formula, Area (A) of the triangle having sides a,b,c units is

A=

s(s−a)(s−b)(s−c)

where

s=

2

a+b+c

For the given triangle,

a=18 cm

b=24 cm

c=30 cm

s=

2

18+24+30

=36

A=

36(36−18)(36−24)(36−30)

A=

36×18×12×6

A=

216×216

=216 cm

2

Smallest side =18 cm

Area of the triangle =

2

1

×base×altitude=216

2

1

×18× altitude=216

Altitude =

9

216

=24 cm

Answered by atharvadityakatiyar1
0

Answer:

answer=24

Step-by-step explanation:

For the given triangle,

a=18 cm

b=24 cm

c=30 cm

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