Question

The area of a triangle is 20 m.sq. If the perimeter is 40 m, then find the length of hypotenuse of the triangle​

Answer 1

Answer is in the attachment please mark me as brainlists

Answer 2

Answer:

BatamaPaisa pani dinxuyestai aajai bachako paniBill banayera aahilai rakhdinu batamai bolayunxuAni maile patha ko photo haru ko sabai pathai dinu 1 set ra kitchen shoes 250 khale 2set thulo ko bachako 1 set pathaidinu voli ma ekai sin ko lagi aayudai xu24,000 is divided into two parts such that the simple interest on the first part for 4 years at 12% per annum is equal to the simple interest on the second part for 6 years at 16% per annum.

So,

Let assume that

First part be x.

Second part be 24000 - x

So,

Case :- 1

Principal, P = x

Rate of interest, r = 12 % per annum

Time, n = 4 years.

We know,

Simple interest (SI) on a certain sum of money of Rs P invested at the rate of r % per annum for n years is given by

\begin{gathered}\boxed{\sf{ \: \: SI \: = \: \frac{P \times r \times n}{100} \: \: }} \\ \end{gathered}SI=100P×r×n

So, on substituting the values, we get

\begin{gathered}\rm \: SI_{1} \: = \: \dfrac{x \times 12 \times 4}{100} = \dfrac{48x}{100} - - - (1) \\ \end{gathered}

512.50 (D)

Step-by-step explanation:

☆Given:

The difference between compound intrest and

Simple intrest is 12.5

☆To find

Principle and compound intrest

☆Solution:

▪P = ?

▪I = 5%

▪N = 2

P[(1+i)^n-1]P[(1+i)n−1] - p × i × t = 12.5

P[(1+0.05)^2-1]P[(1+0.05)2−1] - p × (⁵/₁₀₀) × 2 = 12.5

[(1.05)^2-1] = 0.1025[(1.05)2−1]=0.1025

0.1025p - \frac{10p}{100}10010p = 12.5

\frac{10.25p-10p}{100}10010.25p−10p = 12.5

0.25p = 1250

P= 1250 ÷ .25 = 5,000

CI = P[(1+i)^n-1]CI=P[(1+i)n−1]

CI = 5000 [(1.05)^2-1]

CI = 5000 × 0.1025

CI = 512.50

Step-by-step explanation:

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