Question

the area of a triangle is 40 sq cm . if height of the triangle is 8 cm, then find its base .
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Answer 1

$\:\:\:\: \large \underline {\sf{Given\::}}$

• Area of ∆ = 40 cm²
• Height of ∆ = 8 cm

$\:\:\:\: \large\underline {\sf{To\:Find\::}}$

• Base of ∆

$\:\:\:\: \large\underline {\sf{Solution\::}}$

Let the base be " b "

$\underline{\boxed{\sf{\purple{Formula\:used\:=\: \dfrac{1}{2} \times base \times height}}}}$

$\implies \sf 40\:=\: \dfrac{1}{2} \times b \times 8$

$\implies \sf 8b\:=\: 40 \times 2$

$\implies \sf 8b\:=\: 80$

$\implies \sf b\:=\: \cancel \dfrac{80}{8}$

• Hence,

$\:\:\:\:\:\:\: \Large {\underline{\underline{\sf{Base\:=\:10\:cm}}}}$

Answer 2

Area of triangle = 1/2 x b x h

40 sq cm = 1/2 x b x 8

40 = 4b

4b = 40

b = 40/4

b = 10

The base of the area is 10cm