Question

The area of a triangle is 48 cm square. The height of the triangle is 6cm. Calculate the length of the base.

Answer 1

Given:

• Area of a triangle = 48 cm²
• Height of the triangle = 6 cm

To Find:

• Length of the base = ??

Formula Used:

$\boxed{\mathtt{Area\: of\:Triangle=\dfrac{1}{2}(B \times H)}}$

Solution:

As we know,

$\mathtt{Area_{(Triangle)}=\dfrac{1}{2}(B \times H)}$

Where,

B = Base

H = Height

After substituting values,

$48cm^2=\dfrac{1}{2}(B \times 6)$

After opening brackets, we get:

$48=\dfrac{1}{2}\times 6B$

After multiplying ½ with 6B,

$48= 3B$

After transposing 3 from RHS to LHS and changing its sign,

$\dfrac{48}{3}= B$

After dividing 48 by 3,

$16= B$

Hence, length of the base of the triangle is 16 cm.