Question

The area of a triangle is 48cm^2. its base is 12cm. find its altitude

Answer 1

Area of triangle = 48cm^2
Base of triangle = 12cm

Area of triangle = 1/2 × base × altitude
48cm^2 = 1/2 × 12cm × altitude
(48cm^2 × 2) / 12cm = altitude
96cm^2 / 12cm = altitude
8 cm = altitude

Therefore altitude of the triangle is 8cm

Answer 2

Answer:

$\underline\mathfrak{Given:-}$

$\: \: \: \: \: Area \: \: of \: \: triangle \: \: = \: \: {48} \: {cm}^{2}$

$\: \: \: \: \: base \: \: = \: \: {12} \: {cm}$

$\underline\mathfrak{To \: \: Find:-}$

$\: \: \: \: \: find \: \: its \: \: altitude.?$

$\underline\mathfrak{Solutions:-}$

48=1/2× base×altitude

48= 1/2×12×altitude

altitude = 8cm