The area of a triangle is 48cm2. If the altitude exceeds the
base by 4cm, then the base is:
Answers
To find :-
- The base of the Triangle .
we have :-
- The Area of the Triangle = 48 cm² .
- The altitude of the Triangle exceeds the base by 4 cm . or, base of Triangle = ( altitude – 4 )
Formula used :-
Area of Triangle = 1/2 × Base × Height
Solution :-
- let altitude of the Triangle = x cm .
- as given in question that altitude is exceeds the base by 4 cm . so, base of the Triangle = ( x – 4 ) cm .
Area of Triangle = 1/2 × Base × Height
put the values of altitude and base and Area of Triangle in the formula we get :-
here, we have get the value of altitude .
- x = 12 or,
- x = – 8
- side never would be in negative .
Therefore, altitude of the Triangle is 12 cm .
so, base of the Triangle = ( altitude – 4 ) = 12 – 4 = 8 cm .
The required values of Altitude and Base of the Triangle is 12 cm and 8 cm respectively .
Answer:
Step-by-step explanation:
To find :-
The base of the Triangle .
we have :-
The Area of the Triangle = 48 cm² .
The altitude of the Triangle exceeds the base by 4 cm . or, base of Triangle = ( altitude – 4 )
Formula used :-
Area of Triangle = 1/2 × Base × Height
Solution :-
let altitude of the Triangle = x cm .
as given in question that altitude is exceeds the base by 4 cm . so, base of the Triangle = ( x – 4 ) cm .
Area of Triangle = 1/2 × Base × Height
put the values of altitude and base and Area of Triangle in the formula we get :-
here, we have get the value of altitude .
x = 12 or,
x = – 8
side never would be in negative .
Therefore, altitude of the Triangle is 12 cm .
so, base of the Triangle = ( altitude – 4 ) = 12 – 4 = 8 cm .
The required values of Altitude and Base of the Triangle is 12 cm and 8 cm respectively .