Question

the area of a triangle is 5 sq units. Two of its vertices are (2,1)&(3-2) the third vertex lines y=x+3 find the third vertex​

Answer 1

Answer:

1/2

Step-by-step explanation:

area of a triangle= 1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]

1/2[2(-2-x+3)+3(x+3-1)+x(1+2)]

1/2[2-2x+6+3x+3x]

1/2[4x+8]

this is equal to 5

2x+4=5

2x=1

x=1/2