Question

the area of a triangle is 5 square units two of its vertices are (2, 1) and (3, - 2) if the third vertex is (7/2,y) by then find the value of Y

Answer 1

Given that,
A(x₁,y₁) = (2,1)
B(x₂,y₂) = (3,-2)
C(x₃,y₃) = (7/2,y)
Area of the triangle = 5 sq. units
y = ?
Solution:
Area of triangle = 1/2 I x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂) I
5 = 1/2 I 2(-2-y) + 3(y-1) + 7/2(1+2) I
5 = 1/2 I -4-2y+3y-3+7/2+7 I
5 = 1/2 I -7+7+y+7/2 I
5 = 1/2 I y+7/2 I
10 = I y+7/2 I
10 = y+7/2      ,      -10 = y+7/2
y = 10 - 7/2     ,        y = -10-7/2
y = (20-7)/2     ,        y = (-20-7)/2
y = 13/2          ,         y = -27/2
These are the required values of y.
Thanks.

Answer 2

here is the answer
hope it help u