The area of a triangle is 50 cm2 . if the altitude is of 8 cm , what is the length of its base plz.....
Answers
Answered by
4
hey mate!!
here is your answer:
area of triangle =1/2×base × height
so, 50=1/2×base×8
i.e 50=base×4
50/4=base
12.5cm=base
hope it helped!!
here is your answer:
area of triangle =1/2×base × height
so, 50=1/2×base×8
i.e 50=base×4
50/4=base
12.5cm=base
hope it helped!!
tushinonu01:
how 4 come
1/2×8=4
ok..
its good dude
The diagonal of a rhombus bisect each other at right angle . Use this fact to find the area of rhombus whose diagonal are of length 8cm and 6 cm.
how
ans
area of 1 triangle=1/2×8×3=12cm^2 and area of 2 triangle=1/2×6×4=12cm^2, so area of rhombus=triangle1+triangl2=12+12=24cm^2
Answered by
0
Answer:
Step-by-step explanation:
Given,
Area of triangle=50cm2
Altitude = 8cm
Therefore area=1/2*base*height
Therefore 50=1/2*base*8
Base=50/4cm=1250/100=12.5cm
So,base=12.5cm.
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