Question

The area of a triangle is 60 cm^2 and its base is 12 cm. What is the perpendicular height, in cm, of the triangle? 2 points

Answer 1

Given :

• Area of triangle = 60 cm²

• Base of triangle = 12 cm

To Find :

• Perpendicular height of triangle

Solution :

$\large \boxed{ \boxed{\sf Area_{triangle} = \frac{1}{2} \times base \times height }} \\ \\\sf \implies60 = \frac{1}{2} \times 12 \times h \\\\\sf \implies 60 = 6 \times h \\\\\sf \implies h = \frac{60}{6} \\\\ \implies \boxed {\boxed{ \sf h = 10 \: cm}}$

$\large \underline{ \sf Height \: of \: triangle \: is \: 10 \: cm : }$

Answer 2

Given:

• Area of a triangle = 60 cm²

• Base of triangle ( b ) = 12 cm

To find out:

Find the height ( h ) of given triangle?

Formula used :

Area of triangle = 1/2 × base × height

Solution:

Area of triangle = 1/2 × base × height

Substituting the values in the above formula, we get

⇒ 60 = 1/2 × 12 × h

⇒ 60 = 6 × h

⇒ h = 60/6

⇒ height, h = 10 m

Hence, Height of the triangle is 10 m.

Additional information:

Triangle: A plane figure bounded by three lines in a plane is called triangle.

➔ Sum of the three angles of a triangle is 180°

A triangle with one angles a right angles is called a right angled triangle.