The area of a triangle is 60 sq.cm. and the length of it's one side is 12 cm. What is the lenght of the perpendicular to this side?
a)60cm b)30cm
c12cm d)10cm
Answers
Step-by-step explanation:
Using that in the given question,we now have a right angled triangle with its hypotenuse 13cms long and area 30sqcm.
Let the base of the new Triangle be x
So the altitude becomes √(13² - x²)
½(x)(√(13²-x²))=30
Answer=2x=10 or 24
Answer:
The length of one of the equal sides is 13 cm and the area of the isosceles triangle is 60 sq cm.
If you see the Pythagorean triplets, a hypotenuse of 13 units will have the other two sides as 5 and 12. From this you can see there are two possibilities:
(1) base of right-angled triangle is 12 cm and the height 5 cm. This gives the area as 12*5/2 = 30 sq cm. And the isosceles triangle which is the mirror image of the right-angled triangle about the vertical side has a base of 24 cm and its height is 5 cm. The area of the isosceles triangle = 24 *5/2 = 60 sq cm.
(2) base of right-angled triangle is 5 cm and the height 12 cm. This gives the area as 5*12/2 = 30 sq cm. And the isosceles triangle again which is the mirror image of the right-angled triangle about the vertical side has a base of 10 cm and its height is 12 cm. The area of the isosceles triangle = 10 *12/2 = 60 sq cm.
Thus the isosceles triangle can have (1) a base of 24 cm and height of 5 cm or (2) a base of 10 cm and height of 12 cm.
Take your pick!
Step-by-step explanation:
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