Question

The area of a triangle is 60 sq cm . if its base is 10 cm , what is its height?​

Answer 1

$\sf \large \underbrace{ \underline{Understanding \: the \: Question}}$

As area and base of triangle are given and we have to find height of triangle which we can simply find by applying the formula to find area of triangle.

So let's start!

$\sf★Area \: of \: ∆= \frac{1}{2} ×base×height$

$\sf : \implies \: \: 60cm²= \frac{1}{2} \times 10 \times height$

$: \implies \: \:\sf\cancel\frac{60cm {}^{2} \times 2}{10} = height$

$\sf : \implies \: \: 12cm = height$

So height of ∆ is 12cm.

$\setlength{\unitlength}{1cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(.3,2.5){\large\bf h}\put(2.8,.3){\large\bf 10cm}\put(1.02,1.02){\framebox(0.3,0.3)}\put(.7,4.8){\large\bf A}\put(.8,.3){\large\bf B}\put(5.8,.3){\large\bf C}\qbezier(4.5,1)(4.3,1.25)(4.6,1.7)\put(3.8,1.3){\large\bf }\end{picture}$

NOTE-Kindly visit web to see diagram.

$\sf \large \underbrace{ \underline{More \: formulae \: to \: know}}$

★Area of rectangle=length×breadth

★Area of square=Side²

★Perimeter of square=4×Side

★Area of circle=πr²

★Perimeter of circle=2πr

★Area of triangle=½×base×Height

★Perimeter of triangle=sum of all sides.

Answer 2

Answer:

The height of the traingle is 12 cm.

Step-by-step explanation:

Solution:

Area of the triangle = 60 sq. cm

Base of the triangle = 10 cm

Height of the triangle = ??

Let the height be 'y'.

To get the solution of this question, one needs to have the clear idea of formula we'll be using here.

$\boxed{\sf{Area \: of \: Triangle = \dfrac{1}{2} \times Base \times Height}}$

$\longrightarrow \: {\sf{60 = \dfrac{1}{2} \times 10 \times y}}$

$\longrightarrow \: {\sf{60 = 5 \times y \: \: \gray{(reduce \: 2 \: and \: 10)}}}$

$\longrightarrow \: {\sf{y = \dfrac{60}{5}}} \\\\ \longrightarrow \: {\sf{y = 12}}$

Height = 12 cm

Therefore, the height of the traingle is 12 cm.