Question

the area of a triangle is 600 sq.cm and its base is 80cm it altitude

Answer 1

$\textsf{Answer :}$

$\textsf{Explaination :}$

$\tt{\rightarrow Area \: of \: Triangle = \dfrac{1}{2} \times Base \times Height}$

$\tt{\large{\rightarrow 600 = \dfrac{1}{2} \times 80 \times x}}$

$\tt{\large{\rightarrow 600 = \dfrac{1}{\cancel{2 } \: ^{1} }\times {\cancel{80}}}}^{40} \times x$

$\tt{\large{\rightarrow 600 = 40 \times x}}$

$\tt{\large{\rightarrow600 = 40x }}$

$\tt{\large{\rightarrow 40x = 600}}$

$\tt{\large{\rightarrow x = \dfrac{600}{40} }}$

$\tt{\large{\rightarrow x = \dfrac{ \cancel{600} \: ^{15} }{\cancel{40} \: \: ^{1} }}}$

$\tt{\large{\rightarrow x = 15}}$

$\therefore$The altitude is 15cm

$\textsf{Verification :}$

$\tt{\large{\rightarrow 600 = \dfrac{1}{2} \times 80 \times 15 }}$

$\tt{\large{\rightarrow 600 = \dfrac{1}{\cancel{2 } \: ^{1} }\times {\cancel{80}}}}^{40} \times 15$

$\tt{\large{\rightarrow 600 = 40 \times 15}}$

$\tt{\large{\rightarrow 600 = 600}}$

$\therefore$The altitude of the triangle is 15cm.

Answer 2

Answer:

Altitude will be 15cm.

Step-by-step explanation:

We know that,

Area of a ∆ = ½ × base × height

⟹ 600cm² = ½ × 80 × height

⟹ 600 * 80/2 = height

⟹ 600/40 = height

⟹ height = 15cm ans.