Question

The area of a triangle is 600 sq cm. If it’s base and corresponding altitude are in the ratio of 4:3, find their lengths.

Answer 1

let the base and height of triangle be 4x and 3x because ration given

Answer 2

Base  = 40 cm

Altitude  = 30 cm

Given:

The area of a triangle is 600 sq cm. If it’s base and corresponding altitude are in the ratio of 4:3.

To find:

Their lengths.

Formula used:

The area of a triangle = $\frac{1}{2}$ × Base × Altitude

Explanation:

The triangle base and corresponding altitude are in the ratio of 4:3.

So consider that Base = 4x and Altitude = 3x

The area of a triangle = $\frac{1}{2}$ × Base × Altitude

                   600 = $\frac{1}{2}$  ×  4x × 3x

                     1200 = 12 x²

                           x² = $\frac{1200}{12}$

                          x ² = 100

                           x = 10

Base = 4x = 4×10 = 40 cm

Altitude = 3x = 3×10 = 30 cm

To learn more...

1)The area of a triangle is 1/2 base x altitude. the base of the triangle is 5x cm whereas the altitude is 1/2 of the base. find the area of the triangle.

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2)Calculate the area of the triangle whose vertices are (1,1) , (2,3) ,(4,5)

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