Question

The area of a triangle is 600sq cm. If its base and the corresponding altitude are in the ratio of 4:3, find their lengths.

Answer 1

The area of triangle = 6000cm sq
let the base be 4x and altitude be 3x.
Now,
Area of triangle = 1/2 × base × altitude
6000cm^2 = 1/2 × 4x × 3x
6000cm^2= 2x × 3x
6000/6 = x
1000cm = x
Now, base = 2x = 2×1000 = 2000 cm
altitude= 3x = 3 × 1000=3000cm

Answer 2

Ar of triangle        = 1/2 (base) (height)
           600sq .m   = 1/2 (4x)(3x) 
           600 (2)       = 12x.sq.
           1200          = 12x.sq
           1200/12     = x.sq
            root 100    = x
            10             = X
  Therefore * Altitude = 3x = 3(10) = 30m
                   * Base = 4x =  4(10) = 40m