The area of a triangle is 72 cm^2 and the three altitudes measure 24 cm, 18 cm, and 16 cm. Find the perimeter of the triangle.
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Let the sides of the triangle be
A, B and C.
Given heights,
24,18 and 16cm.
ar.(tr.ABC)=1/2 x bxh
72 =1/2xAx24 = 1/2xBx18 = 1/2xCx16
=>A = 72x2 B = 72x2 C = 72x2
- - - - - - - - - - - -
24. 18. 16
=>Perimeter of the tr.ABC = A+B+C = 6+8+9 = 23cm.
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A, B and C.
Given heights,
24,18 and 16cm.
ar.(tr.ABC)=1/2 x bxh
72 =1/2xAx24 = 1/2xBx18 = 1/2xCx16
=>A = 72x2 B = 72x2 C = 72x2
- - - - - - - - - - - -
24. 18. 16
=>Perimeter of the tr.ABC = A+B+C = 6+8+9 = 23cm.
Hope this will help you.
If you like my answer
Please mark it as brainliest
And
Be my follower if possible.
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