The area of a triangle is 72 cm and the three altitude measures 24 cm, 18 cm, 16 cm. Find the perimeter of the triangle.
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Answer:
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Perimeter of right triangle = 72
a+b+c= 72 _____________ (1)
its area = 216
2
1
ba=216
ba=432 ___________ (2)
∴c
2
=a
2
+b
2
(By pythagoras theorem )
(a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ac
(72)
2
=c
2
+c
2
+2ab+2bc+2ac
5184=2c
2
+2ab+2bc+2ac
5184=2c
2
+2ab+2c(b+a)
5184=2c
2
+2ab+2c(72−c)
5184=2c
2
+2ab+144c−2c
2
5184=2ab+144c
5184=2×432+144c
c=
144
9320
c=30
putting c in equation (1)
a+b+c=72
a+b=72-30
a+b=42.
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