the area of a triangle is 72cm² and the three altitudes measures 24 cm, 18cm,16cm.Find the perimeter of the triangle.
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24×1÷2×@=72
@=6m
18×1÷2×$=72
$=8
16×1÷2×¥=72
¥=9
@+¥+$=perimeter
6+9+8=23m
@=6m
18×1÷2×$=72
$=8
16×1÷2×¥=72
¥=9
@+¥+$=perimeter
6+9+8=23m
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