The area of a triangle is 90 CM ². If it's base is 15 CM, find its altitude
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Answered by
5
Given:Let triangle ABC be the required triangle.
To find: Altitude
Construction: Draw seg AD perpendicular to BC
Solution:Altitude=Height of triangle.
Let triangle ABC be triangle with base=BC and height=AD
Area of triangle=1/2×base×height
= 1/2×BC×AD
90=1/2×15×AD
90×2/15=AD
Therefore,AD=12cm
To find: Altitude
Construction: Draw seg AD perpendicular to BC
Solution:Altitude=Height of triangle.
Let triangle ABC be triangle with base=BC and height=AD
Area of triangle=1/2×base×height
= 1/2×BC×AD
90=1/2×15×AD
90×2/15=AD
Therefore,AD=12cm
Answered by
5
Hey..
Area of a triangle =1/2*base*height or altitude
Given area =90 and base =15
put it in the formula
area =1/2*15
90=1/2*15
The answer will be 12 cm
hope it helps
Mark my answer as brainliest pls
thanq
- ANSHIKA
Area of a triangle =1/2*base*height or altitude
Given area =90 and base =15
put it in the formula
area =1/2*15
90=1/2*15
The answer will be 12 cm
hope it helps
Mark my answer as brainliest pls
thanq
- ANSHIKA
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