Question

The area of a triangle is equal to that of a square of side length 40 cm . find the side of the triangle whose corresponding altitude is 64 cm

Answer 1

Solution

area of the triangle =area of the square

=40²cm²

now....

area of the triangle

=0.5×base × altitude

=(0.5×base ×64)cm²

=(32×base)cm²

now according to the problem

$32 \times base = 40 {}^{2} \\ = > base = \frac{40 {}^{2} }{32} = 50 \: cm$

therefore the side of the triangle is =50 cm

Hope this helps you......

Answer 2

The side of the triangle is 50 cm.

Step-by-step explanation:

Consider the provided information.

The side length of square is 40 cm.

The area of square can be calculated as: $A=(side)^2$

Substitute side = 40 in above formula.

$A=(40)^2$

$A=1600$

Hence, the area of square is 1600 cm².

The area of triangle is: $A=\frac{1}{2}\times\text{b}\times\text{h}$

Where b is the base and h is the height.

It is given that the altitude is 64 cm. Also the area of a triangle is equal to that of a square of side length 40 cm.

Therefore,

$1600=\frac{1}{2}\times\text{b}\times{64}$

$}\text{b}=\frac{1600\times 2}{64}$

$}\text{b}=\frac{1600}{32}$

$}\text{b}=50$

Hence, the side of the triangle is 50 cm.

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The area of a triangle is equal to that of a square whose each side measures 60 m. find the side of the triangle whose corresponding altitude is 90 m.