Question

The area of a triangle is equal to the area of a square whose each side measures 10 m. Find
the length of the side of a triangle corresponding to the altitude measuring 5 m.


pls tell its hard to find for help me pls​

Answer 1

$\large \sf\underline{ \underline{ \red{given : }}}$

• Side of square = 10m

• Area of triangle = Area of square

• Altitude ( height ) of triangle = 5m

$\\ \\\large \sf\underline{ \underline{ \red{to \: fin d: }}}$

• Length of triangle.

$\\ \\ \large \sf\underline{ \underline{ \red{solution : }}}$

We know ,

$\boxed{ \rm{area \: of \: square = {side}^{2} }}$

Area (square) = 10²

$\therefore \: \sf{area \: of \: square \: is \: 100 {m}^{2} }.$

Given that ,

• area of square = area of triangle.

So, Area of triangle = 100m²

$\boxed{ \rm{area \: of \:t rinagle = \frac{1}{2} \times length \times height }}$

$\\ \sf{ 100 = \frac{1}{2} \times length \times height } \\ \\ \\ \sf{ 100 = \frac{1}{2} \times \: length \times 5} \\ \\ \\ \sf{length = \frac{ \cancel{ {100}} \: \: ^{20} \times 2}{ { \cancel5} \: ^{1} } } \\ \\ \\ \therefore \boxed{ \rm{ \green{length = 40m}}}$

Hence , length of triangle is 40m.