Question

the area of a triangle is given 2 /5 square foot what will be the hypotenuse (and one side is 6/5 foot )

Answer 1

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Answer 2

$Given \:area \: of \:a \: triangle (A) \\= \frac{2}{5} \: square \:feet$

$One \: side (b) = \frac{6}{5} \: feet$

$Let \: second \: side = h \: feet$

$i)Now , A = \frac{2}{5} \: square \:feet$

$\implies \frac{1}{2} \times bh = \frac{2}{5} \: square \:feet$

$\implies \frac{1}{2} \times \frac{6}{5} \times h = \frac{2}{5} \: square \:feet$

$\implies h = \frac{2 \times 2\times 5 }{5 \times 6 } \\= \frac{2}{3} \:feet$

$ii) Hypotenuse (h) = \sqrt{b^{2} + h^{2}} \\=\sqrt{( \frac{6}{5})^{2} +( \frac{2}{3})^{2} } \\= \sqrt{ \frac{36}{25} + \frac{4}{9} }\\= \sqrt{\frac{324+100}{225} } \\= \sqrt{\frac{424}{225}} \\= \frac{20.59}{15} \\= 1.37 \: feet$

Therefore.,

$\red{Length \:of \: Hypotenuse} \green{ = 1.37 \: feet }$

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