Question

The area of a triangle of base 40cm is 420 cm^2. What is its altitude

Answer 1

Hello Chitti Here your answer
As you know
$area \: of \: triangle = \frac{1}{2} \times base \times altitude$
Base =40 cm
AREA=420 cm²
A/Q
$\frac{1}{2} \times 40 \times altitude = 420 \\ (transfering \: 40 \: and \: 2 \: to \: rhs) \\ altitude = 420 \times \frac{2}{40} \\ altitude = 21 \: cm$
hOpe you understand

Answer 2

$<b>$ hey mate

here's your answer,

base of a triangle = 40cm

area of a triangle = 420${cm}^{2}$

》 area of triangle = $\huge\frac{1}{2}$ × base × height

》 420 ${cm}^{2}$ = $\huge\frac{1}{2}$ × 40 cm × height

》 420 ${cm}^{2}$ = 20cm × height

》 $\huge\frac{420}{20}$cm = height

》 21 cm = height

$\therefore$ the height of a triangle with base is 40cm and area is 420 ${cm}^{2}$ is 21 cm


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hope it helps you mate

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be brainly