Question

The area of a triangle of sides 28cm,15cm and 41cm is 126 sq cm.The height(altitude)
corresponding to the base 28 cm.

Plz help fastt

Answer 1

Area of triangle = 1/2*base*height

126cm^2 = 1/2*28*height

height = 126*2/28

height = 126/14

height = 9 cm

Answer 2

Answer:

Height = 9 cm

Step-by-step explanation:

Area = 1/2*base*height

$126 = \frac{1}{2} \times 28 \times h \\ = > h = \frac{126 \times 2}{28} \\ = > h = \frac{252}{28} \\ = > \fbox{h = 9cm}$

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