Question

The area of a triangle, the two sides which are 8cm and 11cm the perimeter is 32cm is k_/30 cm ^2. Find the value of k.​

Answer 1

Let one side be a cm then we have,

Perimeter of triangle= Sum of all sides

= 32=8+11+a

=a=13

Now area of sides=√s(s-a)(s-b)(s-c)

s=(a+b+c)/2=(8+11+13)/2=32/2=16

Now, Area=√16(16-13)(16-8)(16-11)

Area=√16(3)(8)(5)

Area=8√30cm^2

Hence, value of k is 8

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