Question

The area of a triangle, two sides of which are 8 cm & 11 cm and the perimeter
is 32 cm is √30ଶ
. Find the value of ‘k
need help

Answer 1

Let a,b,c be the sides of the given triangle and 2s be its perimeter such that

a =8 cm, b =11 cm and 2s =32 cm

Now, a+b+c=2s

8+11+c=32

c=13

Therefore,

s−a=16−8=8,s−b=16−11

=5,s−c=16−13=3

Hence, area of given triangle =

s(s−a)(s−b)(s−c)

=16×8×5×3=830 cm²

Answer 2

Answer:

The area of a triangle, two sides of which are 8 cm & 11 cm and the perimeter

is 32 cm is √30ଶ

. Find the value of ‘k