Question

the area of a triangle whose base and corresponding altitude are 16 cm and 7 cm respectively is equal to the area of a right angle triangle in which one of the sides containing the right angle is 14 cm find the other side of right triangle​

Answer 1

Answer:

Length of other side is 8 cm.

Step-by-step-explanation:

From the properties of triangles :

• Area of triangle =1 / 2 x base x height

Given,

Area of ∆ ( base - 16 cm & height - 7 cm ) = area of ∆ ( base or height - 14 cm ) { let the length of other side be a }

= > 1 / 2 x 16 cm x 7 cm = 1 / 2 x 14 cm x a

= > 16 x 7 cm = 14 x a

= > 8 x 14 cm = 14 x a

= > 8 cm = a

.Hence the length of other side is 8 cm.

Answer 2

Question :--- The area of a triangle whose base and corresponding altitude are 16 cm and 7 cm respectively is equal to the area of a right angle triangle in which one of the sides containing the right angle is 14 cm find the other side of right triangle ?

Formula used :--

→ Area of ∆ = 1/2 * Base * Altitude .

→ Area of Right angle ∆ = 1/2 * Base containing right angle * Perpendicular containing Right angle .

______________________________

Solution :----

Given that :--

→ Base of ∆ = 16cm.

→ Altitude = 7cm.

→ Area of ∆ = (1/2 * 16 * 7 ) cm². ------- Equation (1)

Now,

→ one side containing right angle of ∆ = 14 cm.

→ Let other side containing right angle = x cm.

→ Area of Right angle ∆ = (1/2 * 14 * x ) cm². ---- Equation(2)

Since, it is given that both ∆'s have Same Area .

so, Putting both Equation Equal we get,

→ (1/2 * 16 * 7 ) = (1/2 * 14 * x )

1/2 will be cancel From both sides .

→ 16 * 7 = 14 * x

Dividing both sides by 14 , we get,

→ x = 8cm.

Hence, other side of Right angle ∆ containing Right angle is 8cm.