The area of a triangle whose base and corresponding altitude are 16cm and 7 cm respectively is equal to the area of a right triangle in which one of the sides contains the right angle is 14 cm find the other side of the right triangle
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Step-by-step explanation:
area of the triangle = area of the right triangle
1/2 x 16 x 7 = 1/2 x 14 x bc
16 x 7 = 14 x bc
16 / 2 = bc
bc =8
now in triangle ABC
AC² = AB² + BC²
= 14² + 8²
= 196 + 64
= 260
AC = √260
= 2√65
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