Math, asked by Aarushvir, 11 months ago

The area of a triangle , whose base and the corresponding altitude are 15 cm and 7 cm , is equal to area of a right triangle whose one of the sides containing the right angle is 10.5 cm . Find the other side of this triangle​

Answers

Answered by praharshitharavula
9

Answer:

Given that Base of the right-angled triangle b = 15cm.

Given that Altitude of the right-angled triangle h = 7cm.

We know that Area of the triangle = 1/2 * b * h

                                                         = 105/2

                                                         = 52.5cm^2.

Given that Area of the one side of the triangle = 10.5cm.

Therefore the other side of the triangle = (2 * 52.5)/10.5

                                                                  = 105/10.5

                                                                  = 10cm.

Therefore the other side of the triangle = 10cm

Answered by shivang3632
5

Answer:

10 CM

Step-by-step explanation:

Given that Base of the right-angled triangle b = 15cm.

Given that Altitude of the right-angled triangle h = 7cm.

We know that Area of the triangle = 1/2 * b * h

                                                         = 105/2

                                                         = 52.5cm^2.

Given that Area of the one side of the triangle = 10.5cm.

Therefore the other side of the triangle = (2 * 52.5)/10.5

                                                                  = 105/10.5

                                                                  = 10cm.

Therefore the other side of the triangle = 10cm

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