The area of a triangle , whose base and the corresponding altitude are 15 cm and 7 cm , is equal to area of a right triangle whose one of the sides containing the right angle is 10.5 cm . Find the other side of this triangle
Answers
Answer:
Given that Base of the right-angled triangle b = 15cm.
Given that Altitude of the right-angled triangle h = 7cm.
We know that Area of the triangle = 1/2 * b * h
= 105/2
= 52.5cm^2.
Given that Area of the one side of the triangle = 10.5cm.
Therefore the other side of the triangle = (2 * 52.5)/10.5
= 105/10.5
= 10cm.
Therefore the other side of the triangle = 10cm
Answer:
10 CM
Step-by-step explanation:
Given that Base of the right-angled triangle b = 15cm.
Given that Altitude of the right-angled triangle h = 7cm.
We know that Area of the triangle = 1/2 * b * h
= 105/2
= 52.5cm^2.
Given that Area of the one side of the triangle = 10.5cm.
Therefore the other side of the triangle = (2 * 52.5)/10.5
= 105/10.5
= 10cm.
Therefore the other side of the triangle = 10cm