Question

The area of a triangle whose each angle is
60
0
is 16
√
3
m
2
find its perimeter
.

Answer 1

Area = √3/4 side^2
16√3 = √3/4 side^2
Side ^2 = 16/√3 x 4/√3
Side^ 2 = 64/3
side = 8/√3
Each angle is equal to 60° therefore it is a equilateral triangle
so all sides are equal
Perimeter = 3(side)
= 3(8)/√3 = 24/√3 cm
= 8√3 cm

Answer 2

ar=3 <raise to the power >1/2
let side be x
s=3/2x
ar=
$\sqrt{3 \div 2x \times 1x \div 2 ^{3} }$

${x}^{2} \div 4 \sqrt{3} = \sqrt{3}$

so x=2
perimetre=6