Question

the area of a triangle whose sides are 4 cm 13 centimetres and 15 cm is​

Answer 1

Answer:

Step-by-step explanation: 24 cm^2

we are givne a = 4 cm , b = 13 cm, c = 15 cm

by heron's formula the area of triangle is given as

$\sqrt{s(s-a)(s-b)(s-c)}$

where  $s = \frac{a+b+c}{2}$

s = 32/2 = 16

area = $\sqrt{16(16-4)(16-13)(16-15)}    = 4 \sqrt{12*3} = 4 \sqrt{36}  = 4*6 = 24$ cm^2  Ans.

Answer 2

Answer:

24 cm

Step-by-step explanation:

Given sides of triangle are 4 cm, 13 cm and 15 cm

s=$\frac{a+b+c}{2}$ = $\frac{4+13+15}{2}$ = $\frac{32}{2}$ = $16$

Δ=$\sqrt{s(s-a)(s-b)(s-c)$

=$\sqrt{16(16-4)(16-13)(16-15)$

=$\sqrt{16.12.3.1}$

=$\sqrt{576$

=$24 cm^{2}$

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