Math, asked by dkharaudrina, 6 months ago

the area of a triangle whose sides are 9cm, 12cm and 15cm is​

Answers

Answered by harshitadaswani
1

Area of triangle √s (s-a) (s-b) (s-c)

a = 9 cm , b= 12 cm , c= 15 cm

s= a+b+c/2 = 9+12+15/2

= 36/2 = 18 cm

Area = √18 (18-9) (18-12) (18-15)

=√18 x 9 x 6 x 3

= √9 x 2 x 9 x 3 x 2 x 3

= 3 x 2 x 9

Area = 54 cm²

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