The area of a triangle whose vertices are (0, 0) , (4, 0) and (0, 6) is
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Answered by
1
Answer:
this should have been a math question leave it anyway
Answered by
0
Answer:
4
Step-by-step explanation:
Formula :
Area =1/2[x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]
Solution :
Area =1/2[0(4 + 0) - 0(0 + 0) + 2(0 - 4)]
=1/2[0(4) - 0(0) + 2(-4)]
=1/2(0 - 0 - 8)
=1/2(-8)
Area = 4
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