Question

The area of a triangle whose vertices are (4,-3) (2,5) and. (-3,4) is

Answer 1

Answer:

34 is the correct answer

Answer 2

Answer:

Let the points A, B, C are the vertices of triangle.

A(4,-3), B(2,5), C(-3,4).

Therefore by Centroid formula.

$x = \frac{x1 + x2 + x3}{3} \\ x = \frac{4 + 2 + ( - 3)}{3 } \\ x = \frac{6 + ( - 3)}{3} \\ x = \frac{6 - 3}{3 } \\ x = \frac{3}{3} \\ x = 1$

$y = \frac{y1 + y2 + y3}{3} \\ y = \frac{( - 3) + 5 + 4}{3} \\ y = \frac{ - 3 + 9}{3} \\ y = \frac{6}{3} \\ y = 2$

Area of the triangle is (1,2)

This question is from the lesson

Co-ordinate Geometry