the area of a triangle whose vertices are (5,0), (8,0) and (8,4) (in sq.units) is
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4
according to it
1/2 {x1(y2-y3)+x2(y3-y1)+x3(y1-y2)}
1/2×{-40+32+0}
1/2×(-8)
|-4|
answer is 4
1/2 {x1(y2-y3)+x2(y3-y1)+x3(y1-y2)}
1/2×{-40+32+0}
1/2×(-8)
|-4|
answer is 4
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