Question

The area of a triangle whose vertices are(a,a),(a+1,a+1) and (a+2,a) is

Answer 1

Answer:

X1=a,X2=a+1,X3=a+2,Y1=a,Y2=a+1,Y3=a.

Step-by-step explanation:

area of triangle=1/2(X1(Y2-Y3)+X2(Y3-Y1)+X3(Y1-Y2)). = 1/2(a(a+1-a)+a+1(a-a)+a+2(a-a-1) =1/2(a+0-a-2) =1/2(-2)=|-1|=1. so area of triangle is 1unitsq.