Question

The area of a triangle with sides 11 cm, 12 cm and 13 cm is​

Answer 1

a = 11, b = 12, c = 13

s = (a + b + c)/2

⇒ S=(11+12+13)/2 = 36/2 = 18.

Area (A) = √s(s-a) (s-b) (s-c)

=> Area(A) = √18(18-11)(18-12) (18-13)

Area(A)=√18x7x6x5

Area(A) = 6√105 cm² = 61.48 ~ 61.5cm²

Area(A) = 1/2 x Base x Altitude

Area(A) = 1/2 x 12 x 10.25

=> Area (A) = 61.5 cm²

Hence the statement is True.

Answer 2

Answer:

a = 11, b = 12, c = 13 s = (a + b + c)/2 ⇒ s = (11 + 12 + 13)/2 = 36/2 = 18. Area(Δ) = √s(s-a)(s-b)(s-c) ⇒ Area(Δ) = √18(18-11)(18-12)(18-13) ⇒ Area(Δ) = √18×7×6×5 ⇒ Area(Δ) = 6√105 cm2 = 61.48 ∼ 61.5 cm2 Area(Δ) = 1/2 × Base × Altitude ⇒ Area(Δ) = 1/2 × 12 × 10.25 ⇒ Area(Δ) = 61.5 cm2

Hence the statement is

Step-by-step explanation:

Hope it helps you. Have a good day