Question

the area of a triangle with sides 40m 41m 9m is 180 cm² the altitude to the smallest side is
a)10cm
b)18cm
c)9cm
d)40cm

please answer​

Answer 1

Answer:

Step-by-step explanation:

Correct option is

B

2000

Area of triangular field=  

s(s−a)(s−−b)(s−c)

​

 

s=  

2

a+b+c

​

=  

2

41+9+40

​

=45m

∴ Area of triangular field=  

45(45−41)(45−9)(45−40)

​

 

=4×5×9=180m  

2

 

=180×10  

4

cm  

2

 

now, 900cm  

2

 area required for 1 rose bed

180×10  

4

cm  

2

 area required for  

900

180×10  

4

 

​

rose beds

=2000 rose beds.

Answer 2

Answer:

2000

Area of triangular field=

s(s−a)(s−−b)(s−c)

s=

2

a+b+c

=

2

41+9+40

=45m

∴ Area of triangular field=

45(45−41)(45−9)(45−40)

=4×5×9=180m

2

=180×10

4

cm

2

now, 900cm

2

area required for 1 rose bed

180×10

4

cm

2

area required for

900

180×10

4

rose beds

=2000 rose beds.