Question

The area of a triangle with vertices (-3, 0) (3,0) and (0, k) is 9 sq. units. The value of k will be​

Answer 1

Answer:

k=3

Step-by-step explanation:

area of ∆ = 1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)}]

9= 1/2[-3(0-k)+3(k-0)+0(0-0)]

9=1/2[ -3×(-k)+3k+0]

9=1/2[3k+3k ]

9=1/2×6k

9= 3k

k=3