Math, asked by ayushchakma17, 11 months ago

The area of a triangle with vertices A(3,0), B(7,0) and C(8,4) is

Answers

Answered by anirudhchintu
1

Answer:

calculate AB distance then AC distance. the formula is

1÷2(AB×AC) IN MOD. THE ANSWER IS 2 ( ROOT 41

Answered by kbharathwaj04
2

Answer:

12 sq. units

Step-by-step explanation:

Area of triangle = 1/2[x1 (y2-y3)+x2(y3-y1)+x3(y1-y2)]

                         = 1/2[3(0-4)+7(4-0)+8(0-0)]

                         = 1/2[3(-4)+7(4)+8(0)]

                         = 1/2[-12+28+8]

                         = 1/2[24]

                         = 12.

Therefore the area of the triangle is 12 sq. units.

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