Question

The area of a triangles is 5 squares unit. Two vertices are (2,1) and (3-2). The third vertex lies y=x+3.Find the third vertex
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Answer 1

Answer:

Area of triangle =5squnit

two vertices triangle le,A(2,1),B(3-2),C(x,y)

third vertex lies on the line y=x+3=1

Area

1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=5

(2(-2-y)+3(y-1)+x(1+2)=10

-4-2y+3y-3+3x=10

y+3x=17=(2)

solving (1)and(2)

y+3x=12-x=3/4x=14=7/2

y=7/2+3=13/2

(x,y)=(7/2,13/2)