Question

The area of a triangular board whose sides are 6 cm and 10 cm and the perimeter 24 cm is

Answer 1

Answer:

30cm²

Step-by-step explanation:

area of triangle=1/2×base×height

=1/2×6cm×10cm

=1/2×60cm

=30cm²

hope it helps..

Answer 2

Step-by-step explanation:

Given:-

a triangular board whose sides are 6 cm and 10 cm and the perimeter 24 cm

To find:-

The area of a triangular board whose sides are 6 cm and 10 cm and the perimeter 24 cm

Solution:-

The sides of the triangular board are 6cm and

10 cm

Let a = 6 cm

b=10cm

Let the third side be C cm

Perimeter of a triangle is the sum of all sides

=>Perimeter = a+b+c units

=>Perimeter = 6+10+C cm

=>Perimeter = 16+C cm

According to the given problem

Perimeter = 24 cm

=>16+C = 24 cm

=>C = 24-16

=>C = 8 cm

The third side of the triangle = 8 cm

We know that ,

Area of a triangle whose sides are a,b, c units

is √[s(s-a)(s-b)(s-c) ] sq.units

Where s = Perimeter/2 = (a+b+c)/2

s = 24/2 = 12 cm

Now

On Substituting the values in the above formula

=>√[12(12-6)(12-10)(12-8)]

=>√[12(6)(2)(4)]

=>√[12×12×2×2]

=>√(12×2)^2]

=>√24^2

=>24 sq.cm

Area = 24 sq.cm

(or)

The three sides are 6cm , 10cm and ,8cm

10^2=6^2+8^2

100=36+64

They follow the Pythagoras theorem

They are Pythagorean triplets.

So they are the sides of a right angled triangle

Area of a right angled triangle = ab/2 sq.units

a= 6cm and b=8cm

Area =(6×8)/2

=>48/2

=>24 sq.cm

Area = 24 sq.cm

Answer:-

Area of the given triangular board = 24 sq.cm

Used formulae:-

• Area of a triangle whose sides are a,b, c units is √[s(s-a)(s-b)(s-c) ] sq.units
• s = Perimeter/2 = (a+b+c)/2
• Perimeter of a triangle is the sum of all sides
• Area of a right angled triangle = ab/2 sq.units
• In a right angled triangle,The square of the hypotenuse is equal to the sum of two other sides